2x^2+(x-5)+22=0

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Solution for 2x^2+(x-5)+22=0 equation:


Simplifying
2x2 + (x + -5) + 22 = 0

Reorder the terms:
2x2 + (-5 + x) + 22 = 0

Remove parenthesis around (-5 + x)
2x2 + -5 + x + 22 = 0

Reorder the terms:
-5 + 22 + x + 2x2 = 0

Combine like terms: -5 + 22 = 17
17 + x + 2x2 = 0

Solving
17 + x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
8.5 + 0.5x + x2 = 0

Move the constant term to the right:

Add '-8.5' to each side of the equation.
8.5 + 0.5x + -8.5 + x2 = 0 + -8.5

Reorder the terms:
8.5 + -8.5 + 0.5x + x2 = 0 + -8.5

Combine like terms: 8.5 + -8.5 = 0.0
0.0 + 0.5x + x2 = 0 + -8.5
0.5x + x2 = 0 + -8.5

Combine like terms: 0 + -8.5 = -8.5
0.5x + x2 = -8.5

The x term is x.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
0.5x + 0.25 + x2 = -8.5 + 0.25

Reorder the terms:
0.25 + 0.5x + x2 = -8.5 + 0.25

Combine like terms: -8.5 + 0.25 = -8.25
0.25 + 0.5x + x2 = -8.25

Factor a perfect square on the left side:
(x + 0.5)(x + 0.5) = -8.25

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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